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A bomb is thrown at a speed 20 m//s at a...

A bomb is thrown at a speed `20 m//s` at an angle `45^(@)`. At the highest point , it explodes into two parts of equal mass , the one part coming to rest. Find the distance from the origin to the point where the other part strikes the ground.

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`Range R = (u^(2))/(g) sin 2 theta = ((20)^(2))/(10) sin 90^(@) = 40 m`
The center of mass will hit the ground at `P`
`(m xx (R )/(2) + mx)/(m + m) = R`
`(20 + x)/(2) = 40 rArr x = 60 m`
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