A rocket is set for a vertical firing . If the exhaust speed is `2000 m//s` , find the rate of fuel consumption initial vertical upward acceleration of `30 m//s^(2)`. Take mass of rocket `= 6000 kg`.

Explanation

(a) `v_(r) = 200 m//s , m = 6000 kg`
Upward thrust `v_(r) (dm)/(dt) = mg`
`2000 (dm)/(dt) = (6000) (10) rArr (dm)/(dt) = 30 kg//s`
(b) `a = (v_(r))/(m) (dm)/(dt) - g`
(b) `a = (v_(r))/(m) (dm)/(dt) - g`
`30 = (1000)/(6000) (dm)/(dt) - 10`
`(dm)/(dt) = 240 kg//s`