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Two bodies with kinetix energies in the ...

Two bodies with kinetix energies in the ratio of `4 : 1` are moving with equal linear momentum. The ratio of their masses is

A

`1 : 2`

B

`1 : 1`

C

`4 : 1`

D

`1 : 4`

Text Solution

Verified by Experts

The correct Answer is:
D
`p = sqrt(2 m_(1) K_(1)) = sqrt(2 m_(2) K_(2))`
`(m_(1))/(m_(2)) = (K_(2))/(K_(1)) = (1)/(4)`
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