If the kinetic energy of a body increases by `0.1 %` the percent increase of its momentum will be

Options

A. `0.05 %`
B. `0.1%`
C. `1.0%`
D. `10%`

Answer

A

Explanation

`K_(1) = K,K_(2) = K(1 + (0.1)/(100))`
`(p_(2))/(p_(1)) = sqrt((K_(2))/(K_(1))) = ( 1 + (0.1)/(100))^(1//2) = 1 + (1)/(2) xx (0.1)/(100)`
`((p_(2))/(p_(1)) - 1) xx 100 = (1)/(2) xx 0.1 = 0.05 %`