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A shere of mass m , moving with velocity...

A shere of mass `m` , moving with velocity `V`, enters a hanging bag of sand and stop. If the mass of the bag is `M` and it is reised by height `h`, then the velocity of the sphere will be

A

`(M + m)/(m) sqrt(2 gh)`

B

`(M)/(m) sqrt(2 gh)`

C

`(m)/(M + m) sqrt(2 gh)`

D

`(m)/(M) sqrt(2 gh)`

Text Solution

Verified by Experts

The correct Answer is:
A

`mv = (m + M)v_(1) rArr v_(1) = (mv)/(m + M)`
`v'^(2) = v_(1)^(2) - 2gh rArr 0 = v_(1)^(2) - 2gh`
`v_(1) = sqrt(2 gh)`
`(mv)/(m + M) = sqrt(2 gh)`
`v = (M + m)/(m) sqrt(2 gh)`
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