A ball moving with velocity `2 ms^(-1)` collides head on with another stationary ball of double the mass. If the coefficient of restitution is `0.5`, then their velocities (in `ms^(-1)`) after collision will be

Options

A. `0 , 2`
B. `0 ,1`
C. `1,1`
D. `1 ,0.5`

Answer

B

Explanation

`m xx 2 + 2m xx 0 = mv_(1) + 2mv_(2)`
`rArr v_(1) + 2v_(2) = 2` (i)
`v_(1) - v_(2) = -e( u_(1) - u_(2))`
` = -e( 2 - 0) = -(1)/(2) (2) = -1` (ii)
Solving `v_(1) = 0 , v_(2) = 1 m//s`