Find the equivalent capacitance between `A` and `B`.

Explanation

(a)
Here `C_(1)//C_(2)=C_(3)//C_(4)`, i.e., this is balanced wheatstone bridge.
remove capacitor `(C_(5)=C)` because no charge is stored in it.

(b) .
First, redraw the diagram,

Here, `6C//3C=12C//6C`, a balanced wheatstone bridge, remove capacitor between `X` and `Y`.


(c)
(d) .

Balanced wheatstone bridge, remove capacitor between `X` and `Y`.

`C_(eq)=4C`
Balanced wheatstone bridge, remove capacitor between `C` and `F`.
`C_(eq)=(6C)/(7)`