Find the potential difference and caharge on each capacitences. All capacitance in `muF`.

Explanation

Here, two branches are in parallel. Potential difference across each branch Is `60V`. There are two capacitors in series, use direct formulae as explained earlier.
`V_(1)=((6)/(3+6))xx60=40V, V_(2)=60-V_(1)=20V`
`V_(3)=((18)/(9+18))xx60=40V,V_(4)=60-V_(3)=20V`
charge on
`3muF:3xx40=120muC`
`6muF:6xx20=120muC`
`9muF:9xx40=360muC`
`18muF:18xx20=360muC`
Alternative Method :