A capacitor of `2muF` cahrged to `50V` is connected in parallel with another capacitor of `1muF` cahrged to `20V`. Find common potential, cahrge on each capacitor and the loss the loss of energy.

Explanation

To solve the problem step-by-step, we will follow the outlined process to find the common potential, the charge on each capacitor, and the loss of energy.

### Step 1: Calculate the initial charges on each capacitor

The charge stored in a capacitor is given by the formula:
\[ Q = C \times V \]

For the first capacitor \( C_1 = 2 \mu F \) charged to \( V_1 = 50 V \):
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