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In a capacitor of capacitance 20 muF,the...

In a capacitor of capacitance `20 muF`,the distance between the plates is `2 mm`. If a dielectirc slab of width `1 mm` and dielectric constant `12` is inserted between the plates, then the new capacitance is

A

`2muF`

B

`15.5muF`

C

`26.6muF`

D

`32muF`

Text Solution

Verified by Experts

The correct Answer is:
C
`C'=(Ain_(0))/(d-t+(t)/(K))=(Ain_(0))/(2-1+(1)/(2))=(2)/(3)Ain_(0)`
`=(4)/(3)((Ain_(0))/(2))=(4)/(3)xx20=(80)/(3)=26.6muF`
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CP SINGH-CAPACITANCE-Exercise
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