A series combination of `n_(1)` capacitors, each of value `C_(1)`, is charged by a source of potential difference `4 V`. When another parallel combination of `n_(2)` capacitors, each of value `C_(2)`, is charged by a source of potential difference `V`, it has same (total) energy stored in it, as the first combination has. the value of `C_(2)`, in terms of `C_(1)`, is then

Options

A. `(16C_(1))/(n_(1)n_(2))`
B. `(2C_(1))/(n_(1)n_(2))`
C. `16(n_(2))/(n_(2))C_(1)`
D. `2(n_(2))/(n_(1))C_(1)`

Answer

A

Explanation

`U=(1)/(2)(C_(1))/(n_(1))(4V)^(2)=(1)/(2)n_(2)C_(2)V^(2)`
`C_(2)=(16C_(1))/(n_(1)n_(2))`