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In the following circuit, the resultant ...

In the following circuit, the resultant capacitance between `A` and `B` is `1muF`. Then value of `C` is

A

`(32)/(11)muF`

B

`(11)/(32)muF`

C

`(23)/(32)muF`

D

`(32)/(23)muF`

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(eq)=(Cxx(32)/(9))/(C+(32)/(9))`
`1=(32C//9)/((9C+32)//9)=(32C)/(9C+32)`
`9C+32=32Cimplies23C=32` ltbRgt `C=(32)/(23)muF`
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