The capacities of two parallel plate capacitors are `C_(1)` and `C_(2)` and their respective potential are `V_(1)` and `V_(2)`. If they are connected by a thin wire, then
(A) Commen potential will be `(C_(1)V_(1)+C_(2)V_(2))/(C_(1)+C_(2))`, if plates of same polarities are connected together
(B) Loss of energy will be `(1)/(2)(C_(1)C_(2))/(C_(1)+C_(2))(V_(1)-V_(2))^(2)`, if plates of same polarities are connected together
(C) Common potential will be `(|C_(1)V_(1)-C_(2)V_(2)|)/(C_(1)+C_(2))`, if plates of opposite polarities are connected together

Options

A. `(A),(B),(c)`
B. `(B),(c),(D)`
C. `(A),(B),(D)`
D. `(A),(B),(c),(D)`

Answer

D

Explanation

NA