A condenser of capacity `C_(1)` is charged to a potential `V_(0)`. The electrostatic energy stored in it is `U_(0)`. It is connected to another uncharged condenser of capacity `C_(2)` in parallel. The energy dissipated in the process is

Options

A. `(C_(2))/(C_(1)+C_(2))U`
B. `(C_(1))/(C_(1)+C_(2))U`
C. `((C_(1)-C_(2))/(C_(1)+C_(2)))U`
D. `(C_(1)C_(2))/(2(C_(1)+C_(2)))U`

Answer

A

Explanation

`U=(1)/(2)C_(1)V^(2)`
`DeltaU=(1)/(2)(C_(1)C_(2))/(C_(1)+C_(2))(V-0)^(2)=(C_(2))/(C_(1)+C_(2))U`