A parallel plate air capacitor is connected to a battery. The quantities charge, voltage, electric field and energy associated with this capacitor are given by `Q_0` , `V_0`, `E_0` and `U_0` respectively. A dielectric slab is now introduced to fill the space between the plates with battery still in connection. The corresponding quantities now given by Q, V, E and U are related to the previous one as

Options

A. `A,B`
B. `A,C`
C. `B,C`
D. `A,D`

Answer

D

Explanation

If battery remains connected, potential of capacitor remains same.
`V=V_(0)`
`Q_(0)=CV_(0),Q=KCV=KCV_(0), QgtQ_(0)`
`E_(0)=(V_(0))/(d),E=(V)/(d)=(V_(0))/(d), E=E_(0)`
`U_(0)=(1)/(2)CV_(0)^(2),U=(1)/(2)KCV^(2)=(1)/(2)KCV_(0)^(2),UgtU_(0)`