Home
Class 12
PHYSICS
(i) A pair of stationary and infinitely ...

(i) A pair of stationary and infinitely long bent wires are placed in the XY- plane as shown.The wires carry currents 10 A each. The segment P and Q are parallel to the Y-axis such as OS =OR = 0.02 m. Find the magnitude field at the origin O

(ii) Three long wires carrying currents `10 A` ,`20 A` and `30 A` are placed parallel to each other as shown. Find the magnetic field at P and Q

Text Solution

Verified by Experts

(a) (i)
At `P_(1):`
`B_(1)=(mu_(0)(10))/(2pi(2))=(5mu_(0))/(2pi), o.`
`B_(2)=(mu_(0)(20))/(2pi(2))=(10mu_(0))/(2pi), ox`
`B_(P_(1))=B_(2)-B_(1)=(5mu_(0))/(2pi),ox`
(ii)
At `P_(2):`
`B_(1)=(mu_(0)(10))/(2pi(2))=(5mu_(0))/(2pi), o.`
`B_(2)=(mu_(0)(20))/(2pi(2))=(10mu_(0))/(2pi), o.`
`B_(P_(2))=B_(1)-B_(2)=(15mu_(0))/(2pi),o`.
(iii)
At `P_(3):`
`B_(1)=(mu_(0)(10))/(2pi(2))=(5mu_(0))/(2pi), ox`
`B_(2)=(mu_(0)(20))/(2pi(2))=(10mu_(0))/(2pi), o.`
`B_(P_(3))=B_(2)-B_(1)=(5mu_(0))/(2pi),o.`
(iv)
At `P_(4):`
`B_(1)=(mu_(0)(10))/(2pi(2))=(5mu_(0))/(2pi), ox`
`B_(2)=(mu_(0)(20))/(2pi(2))=(10mu_(0))/(2pi), ox`
`B_(P_(4))=B_(1)+B_(2)=(15mu_(0))/(2pi),ox`
(b)
`B_(P)=(mu_(0)i_(1))/(2pid)-(mu_(0)i_(2))/(2pid)=(mu_(0))/(2pid)(i_(1)-i_(2))=20`

`B'_(P)=(mu_(0)i_(1))/(2pid)-(mu_(0)i_(2))/(2pid)=(mu_(0))/(2pid)(i_(1)+i_(2))=80`
`(i)//(ii)` `(i_(1)-i_(2))/(i_(1)+i_(2))=20/80=1/4`
`4i_(1)-4i_(2)=i_(1)+i_(2)`
`3i_(1)=5i_(2)`
`(i_(1))/(i_(2))=5/3`
(c)
At `P:`
`B_(1)=(mu_(0)i)/(2piy), o.`
`B_(2)=(mu_(0).2i)/(2pix), ox`
Since magnetic field at `P` is zero
`B_(1)=B_(2)`
`(mu_(0)i)/(2piy)=(2mu_(0)i)/(2pix)`
`x=2y`
`2y-x=0`
Locus is a straight line passing through origin

(d)
`B_(1)=B_(4)=0`
`B_(2)=B_(3)=(mu_(0)i)/(4pid), o.`
`B_(O)=B_(2)+B_(3)=(mu_(0)i)/(2pid)=(mu_(0))/(2pi)xx10/0.02=(mu_(0))/(4pi)xx1000`
`=10^(-7)xx10^(3)=10^(-4)T`
(e)
At `Q:`
`B_(Q)=(mu_(0))/(2pi)[30/d-20/d-10/(3d)]`
`=(mu_(0))/(2pi).20/(3d) ox.`
At `P:`
`B_(P)=(mu_(0))/(2pi)[30/(3d)+20/d-10/(d)]`
`=(mu_(0))/(2pi).20/(d)`
`(B_(P))/(B_(Q))=3`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC FIELD

    CP SINGH|Exercise EXERCISE|77 Videos
  • ELECTROSTATICS

    CP SINGH|Exercise Exercises|226 Videos
  • MAGNETIC FORCE, MOMENT AND TORQUE

    CP SINGH|Exercise Exercises|141 Videos

Similar Questions

Explore conceptually related problems

(i) A pair of stationary and infinitely long bent wires are aplced in the XY- plane as shown.The wires carry currents 10 A each. The segment P and Q are parallel to the Y-axis such as OS =OR = 0.02 m. Find the magnitude field at the origin O (ii) three long wires carrying 10 A 20 A and 30 A are placed parallel to each other as shown field at P and Q

A pair of stationary and infintely long bent wires are placed in the XY planes as shown in fig. The wires carry currents of I = 10 amperes each as shown . The segments P and Q are parallel to the Y-axis such that OS = OR = 0.02 m . Find the magnitude and direction of the magnetic induction at the origin O .

Find vecB at the origin due to the long wire carrying current I.

A pair of stationary and infinitely long bent wires is placed in the X-Y plane as shown in figure.The wires carry currents of 10A each as shown.The segments L and M are along the x -axis.The segments P and Q are pallel to the Y -axis such that OS=OR=0.02 m .Find the magnitude and direction of the magnetic induction at the origin O .

Two long wires are placed parallel to each other 10cm apart as shown in figure. The magnetic field at point P is

The direction of magnetic field at a point due to an infinitely long wire carrying current is

Four infinitely long wires carring equal currents are placed parallel and equidistant as shown in figure. Then magnitude of force

A long wire carrying current 'I' is bent into the shape as shown in the figure. The net magnetic field intensity at the centre 'O' is

Two long wires PQR and MNP carry equal current I as shown such that QR and NP are parallel. Find the megnetic field at origin O .

CP SINGH-MAGNETIC FIELD-EXERCISE
  1. (i) A pair of stationary and infinitely long bent wires are placed in ...

    Text Solution

    |

  2. The magnetic field at the origin due to a current element I vec(dl) pl...

    Text Solution

    |

  3. Consider three quantities x=E/B, y=sqrt(1/(mu(0)epsilon(0))) and z=1/(...

    Text Solution

    |

  4. If C the velocity of light, which of the following is correct?

    Text Solution

    |

  5. A vertical wire carriers a current upwards. The magnetic field at a po...

    Text Solution

    |

  6. A moving charge produces

    Text Solution

    |

  7. A circular loop is kept in that vertical plane which contains the nort...

    Text Solution

    |

  8. O is mid-point of AB. The magnetic field at O is

    Text Solution

    |

  9. An infinetely long conductor PQR is bent to from a right angle as show...

    Text Solution

    |

  10. A long straight wire carries the current along +ve x-direction. Consid...

    Text Solution

    |

  11. A straight section PQ of a circuit lise along the X-axis from x=-a/2 t...

    Text Solution

    |

  12. A horizontal overheadpowerline is at height of 4 m from the ground and...

    Text Solution

    |

  13. AB and CD are long staright conductors, distance d apart, carrying a c...

    Text Solution

    |

  14. A straight conductor carriers a current alon the z-axis Consider the p...

    Text Solution

    |

  15. A long wire carrying i is bent to form a plane angle theta.Find the ma...

    Text Solution

    |

  16. A wire carrying current I is shaped as shown. Section AB is a quarter ...

    Text Solution

    |

  17. ABCD is a square loop made of a uniform conducting wire. A current ent...

    Text Solution

    |

  18. In the loop shown, all curved sections are either semicircles or quart...

    Text Solution

    |

  19. Evaluate magnitude and direction of magnetic field at a point P in the...

    Text Solution

    |

  20. A cell is connected between the point A and C of a circular conductor ...

    Text Solution

    |

  21. A battery is connected between two points A and B on the circumference...

    Text Solution

    |