5(x-5)(x+5)=55

Lt_(x to 5) (|x-5|)/(x-5)=

If P(X=x)=(x-5)/(4),x=5.5,6.5,7.5, then

Simplify: (155x155x155-55x55x55)/(155x155+155x55+55x5)

If f(x) = {((x-5)/abs(x-5) ,+, a if x ,lt, 5), (a,+,b if x,=,5), ((x-5)/abs(x-5) ,+, b if x ,gt, 5):}

The co-ordinate of the point on the curve y = 6x - x^2 , the tangent at which, is parallel to the line y =-4x are ....... A) (5,5) B) (5,-5) C) (-5,5) D) (-5,-5)

The coordinates of the point on the curve y=6x-x^(2) the tangent at which is parallel to the line y=-4x are (a) (5,5) (b) (5,-5) (c) (-5,5) (d) (-5,-5)

If x(sqrt(25)^(x+(1)/(4))*sqrt(5.5)^(-1))/(5sqrt(5)^(-x))=p, then find the value of p.

If f[-5,5] to R , is a differentiable function and if f'(x) does not vanish anywhere, then prove that f(-5)!=f(5) .

If f:[-5,5]rarr R is differentiable and if f'(x) doesnt vanish anywhere,then prove that f(-5)!=f(5)

Assertion (A) : (1)/(5)+(1)/(3.5^(3))+(1)/(5.5^(5))+(1)/(7.5^(7))+…(1)/(2)log((3)/(2)) Reason (R ) : If |x| lt 1 then log_(e )((1+x)/(1-x))=2(x+(x^(3))/(3)+(x^(5))/(5)+…)