[" 2."(e^(y)+1)cos xdx+e^(y)sin xdy,=0],[" [Ans.":(e^(y)+1)sin x,=c]]

(e^(y)+1)cos x dx+e^(y)sin x dy =0 A) (e^(y)+1)sin x =c B) (e^(y)+1)=c tan x C) e^(y)sin x + cos x=c D) (e^(x)+1)sin y=c

(e^(y)+1)xdx=(x+1)e^(y)dy

is = e ^ (x + 2y) sin xdx

y(xy+e^x)dx-e^xdy=0

Solve y^'+y cos x=e^(sin x) cos x

The general solution of the equation (e^(y)+1)cos xdx+e^(y)sin xdx=0 is