[" 7) "tan^(-1)3x+tan^(2)2x=pi],[" Find "x']

tan^(-1)2x+tan^(-1)3x=(pi)/(4)

Solve for x, "tan"^(-1)3x+"tan"^(-1)2x=pi/(4) .

solve tan^(-1) 2x + tan^(-1) 3x = pi/4 , if 6x^2 lt 1 .

Solve for x: tan^(-1)3x+tan^(-1)2x=pi/4

Solve for x: tan^(-1)3x+tan^(-1)2x=pi/4

Find the solution of tan^(-1) 2x +tan^(-1) 3x = pi/4 , x gt 0

Let |{:(tan^(-1)x, tan^(-1)2x, tan^(-1)3x), (tan^(-1)3x, tan^(-1)x, tan^(-1)2x), (tan^(-1)2x, tan^(-1)3x, tan^(-1)x):}|=0 , then the number of values of x satisfying the equation is

If Tan^(-1)2x+Tan^(-1)3x=pi//4 , then x =