`log_(1/9)w=log_3 7,` then the value of w is

If A=((log_(3)1-log_(3)4)(log_(3)9-log_(3)2))/((log_(3)1-log_(3)9)(log_(3)8-log_(3)4)) then find the value of 2(3^(A))

If h(x)=log_(10)x, then the value of sum_(n=1)^(89) h"("tan^(Omega)")"=

If x=log_(2a)((bcd)/2), y=log_(3b)((acd)/3), z=log_(4c)((abd)/4) and w=log_(5d)((abc)/5) and 1/(x+1)+1/(y+1)+1/(z+1)+1/(w+1) = log_(abcd)N+1, then value of N/40 is

If x=log_(2a)((bcd)/2), y=log_(3b)((acd)/3), z=log_(4c)((abd)/4) and w=log_(5d)((abc)/5) and 1/(x+1)+1/(y+1)+1/(z+1)+1/(w+1) = log_(abcd)N+1, then value of N/40 is

If x=log_(2a)((bcd)/2), y=log_(3b)((acd)/3), z=log_(4c)((abd)/4) and w=log_(5d)((abc)/5) and 1/(x+1)+1/(y+1)+1/(z+1)+1/(w+1) = log_(abcd)N+1, then value of N/40 is

if log_(49)3 xx log_(9)7 xx log_(2)8 = x then find the value of (4x)/3

Find the value of log_3^(1/9) .

If lot 7- log 2 + log 16 - 2 log3 - log "" (7)/(45)= 1 + log k, find the value of k.

If x=log_(2a)((bcd)/(2)),y=log_(3b)((acd)/(3)),z=log_(4c)((abd)/(4)) and w=log_(5d)((abc)/(5)) and (1)/(x+1)+(1)/(y+1)+(1)/(z+1)+(1)/(w+1)=log_(abcd)N+1, then value of (N)/(40)