" 18."(sqrt(27)-(9)/(sqrt(3))-sqrt((1)/(9))+sqrt((1)/(27)))[" (iv) "3sqrt(3)],[" (i) "sqrt(2)]

sqrt(27)-(9)/(sqrt(3))-root(4)((1)/(9))+root(6)((1)/(27))

7sqrt(3)+2sqrt(27)

3sqrt(4)+2sqrt(9)+5sqrt(4)-sqrt(1)-4sqrt(9)

(sqrt(3)+1)(1-sqrt(12))+(9)/(sqrt(3)+sqrt(12))

Rationalise the denominators of the following : i) (1)/(3+sqrt(2)) ii) (1)/(sqrt(7)-sqrt(6)) iii) (1)/(sqrt(7)) iv) (sqrt(6))/(sqrt(3)-sqrt(2))

Solve the following :- (i) sqrt(sqrt(2)/(3))xxsqrt((9)/(2)) (ii) sqrt((5)/(6))xxsqrt((3)/(5)) (iii) sqrt((3)/(5))divsqrt((27)/(125)) (iv) sqrt((4)/(9))divsqrt((64)/(81))

Solve the following :- (i) sqrt(sqrt(2)/(3))xxsqrt((9)/(2)) (ii) sqrt((5)/(6))xxsqrt((3)/(5)) (iii) sqrt((3)/(5))divsqrt((27)/(125)) (iv) sqrt((4)/(9))divsqrt((64)/(81))

Solve the following :- (i) sqrt(sqrt(2)/(3))xxsqrt((9)/(2)) (ii) sqrt((5)/(6))xxsqrt((3)/(5)) (iii) sqrt((3)/(5))divsqrt((27)/(125)) (iv) sqrt((4)/(9))divsqrt((64)/(81))

(2sqrt(27)-sqrt(75)+sqrt(12)) is equal to sqrt(3)(b)2sqrt(3) (c) 3sqrt(3)(d)4sqrt(3)

Simplify (i) (4+ sqrt(5))/(4-sqrt(5))+(4-sqrt(5))/(4+sqrt(5)) (ii) (1)/(sqrt(3) + sqrt(2)) - (2)/(sqrt(5)-sqrt(3)) -(2)/(sqrt(2) - sqrt(5)) (iii) (2+sqrt(3))/(2-sqrt(3)) + (2-sqrt(3))/(2+sqrt(3)) + (sqrt(3)-1)/(sqrt(3)+1) (iv) (2+sqrt(6))/(sqrt(2)+sqrt(3))+(6sqrt(2))/(sqrt(6)+sqrt(3)) -(8sqrt(3))/(sqrt(6)+sqrt(2))