" 24."quad " aft "A=[[1,1,1],[1,1,1],[1,1,1]]," so Rea "

24. Eigen values of [[1, 1, 1],[1,1,1],[1,1,1]] are (a) 0,00 (b) 0, 01 (c) 0, 0, 3 (d)1, 1, 1

If A = [(2,2,1), (1,3,1), (1,2,2)] then A^-1+(A-5I) (AI)^2 = (i) 1/ 5 [[4,2, -1], [-1,3,1], [-1,2,4]] (ii) 1/5 [[4, -2, -1], [-1, 3, -1], [-1, -2,4]] (iii) 1/3 [[4,2, -1], [-1,3,1], [-1,2,4]] (iv) 1/3 [[4, -2, -1], [-1,3, -1], [-1, -2,4]]

Find the value of x if |[1+x,1-x,1],[2,4+x,3],[-1,1,2]|=0

If A=[[1,3],[-2,4]] Hence find A^(-1)

Show that the points A(3,-2,4),B(1,1,1),C(-1,4,-2) are collinear.

On using elementary operation C_(2) to C_(2) - 2C_(1) in the following matrix equation : [ (1,-3),(2,4)] = [ (1,1),(0,1)] [ (3,1),(2,4)] we have :

Use the elementary column operations C_(2) to C_(2)-2C_(1) in the matrix equation [{:(1,-3),(2,4):}]=[{:(1,-1),(0,1):}][{:(3,1),(2,4):}]

If A= |(2,1),(1,2)|,B=|(2,4),(1,2)| then |AB| is