A conducting liquid bubble of radius a and thickness ` t ( tltlt a)` is charged to potential `V`. If the bubble collapses to a droplet , find the potential on the droplet .

Explanation

Here charge and mass are conserved .If `R` is the radius of the resulting drop formed and `p` is density of soap solution `(4)/(3)pir^(3)p=4piR^(3)tp rArr R=(3r^(2)t)^(1//3)`
Now potential of the bubble is `V=(1)/(4piepsilon_(0))(q)/(r )`
or `q=4piepsilon_(0)rV`
Now potential of resulting drop is
`V^(|)=(1)/(4piepsilon_(0))(q)/(R )=((r)/(3t))^(1//3)V`.