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A mass m carrying a charge q si suspende...

A mass m carrying a charge `q` si suspended form a string and placed in a uniform horizontal electric field of intensity `E`.The angel made by the string with the vertical in the equilibrium position is

A

`theta=tan^(-1)""(mg)/(Eq)`

B

`theta=tan^(-1)""(m)/(Eq)`

C

`theta=tan^(-1)""(Eq)/(m)`

D

`theta=tan^(-1)""(Eq)/(mg)`

Text Solution

Verified by Experts

The correct Answer is:
4
`qE=mg tantheta`
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