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Two point charges -q and +q are located ...

Two point charges `-q` and `+q` are located at points `(0,0-a)` and `(0,0,a)` resepctively.The electric potential at point `(0,0,z)`is `(Z gt a)`

A

`(qa)/(4piepsilon_(0)z^(2))`

B

`(q)/(4piepsilon_(0)a)`

C

`(2qa)/(4piepsilon_(0)(z^(2)-a^(2)))`

D

`(2qa)/(4piepsilon_(0)(z^(2)+a^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
3
the distance of point `P` from charge `+Q` is `r_(1)=z-a` and from, charge `-q` is `r_(2)=z+a`
Potnetial at `P` is
`(1)/(4piepsilon_(0))((q)/(r_(1))-(q)/(r_(2)))=(1)/(4piepsilon_(0))(2qa)/((z^(2)-a^(2)))`
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