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The Gaussian surface for calculating the...

The Gaussian surface for calculating the electric field due to a charge distribution is

A

any closed surface around the charge distribution

B

any surface near the charge distribution

C

a spherical surface

D

a closed surface at a every point of which electric field has a normal components which is zero or a fixed value

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The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that ointbar(E).bar(ds)=(q)/(epsilon_(0)) where ds is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface. Gauss throrem in electrostatics states that electric flux oint(E.ds)=(q)/(epsilon_(0)) where S is the Gaussian surface ,the electric field E is due to all the charges

NARAYNA-ELECTROSTATICS AND GAUSS LAW-C.U.Q
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  2. In the above problem the value of E in the space outside the sheets is

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  5. A point charge q is placed at the centre of a cube. What is the flux l...

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  6. What is the flux through a cube of side 'a' if a point charge of q is ...

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  8. A charge q is enclosed as shown below the electric flux is

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  10. A metallic shell has a point charge 'q' kept inisde its cavity. Which ...

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  13. Assertion. A metallic shield in the form of a hollow shell, can be bu...

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