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In figure two positive charges q(2) and ...

In figure two positive charges `q_(2)` and `q_(1)` fixed along the y-axis ,exert a net electric force in the `+x` direction on a charge `q_(1)` fixed along the `x-axis` if a positive charge `Q` is added at `(x,0)` the force on `q_(1)`

A

shall increase along the positive x-axis

B

shall decrease along the positive x-axis

C

shall point along the negative x-axis

D

shall increase but the direction changes because of the intersection of `Q` and `q_(2)` and `q_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
Since positive charges `q_(2)` and `q_(3)` exert a net force in the `+x` direction on the charge `q_(1)` fixed along the `x-axis` the charge `q_(1)` is negative.Obviously due to addition of positve charge `Q` at `(x,0)` the force on `-q` shall increase along the positve x-axis
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Knowledge Check

  • In the figure two positive charges q_2 and q_3 fixed along the Y-axis, exert a net electric force in the + x direction on a charge q_1 fixed along the X-axis. If a positive charge Q is added, at {x, 0), the force on q_1

    A
    shall increase along the positive X-axis
    B
    shall decrease along the positive X-axis
    C
    shall point along the negative X-axis
    D
    shall increase but the direction changes because of the intersection of Q with `q_2`and `q_3`

  • The given figure gives electric line of force due to two charges q_(1) and q_(2) . What are the signs of the two charges ?

    A
    Both are negative
    B
    Both are positive
    C
    `q_(1)` is positive but `q_(2)` is negative
    D
    `q_(1)` is negative but `q_(2)` is positive

  • A positive point charge (q) is projected along (+x) axis electric field is directed along (-y) axis E = E_0(-hatj) Find trajectory of charge after x = d.

    A
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    B
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    C
    `y = qE_0d/(2m(v_0)^2)*(d/2 -x)`
    D
    `y = qE_0d/(2m(v_0)^2)*(d/2 +x)`

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