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If oint(s) E.ds = 0 Over a surface, then...

If `oint_(s) E.ds = 0` Over a surface, then

A

the electric field inside the surface and on it is zero

B

the electric field inside the surface is necessary uniform

C

the number of flux lines entering the surface must be equal to the number of flux lines leaving it

D

all charges must necessarily be outside surface

Text Solution

Verified by Experts

The correct Answer is:
C,D
According to Gauss's law `ointE.dvec(S)=(q)/(epsilon_(0))`
Here `oint_(S)vec(E).dvec(S)` represent the total electric flux over a closed surface `S` and `q` ,represents the charge enclosed by this surface.so for `oint_(S)vec(E).dvec(S)=0` the number of flux lines entering the surface must be equal to the number of lines leaving it and charge enclosed by the surface should be zero.i.e, all charges must necessarily be outside the surface .Options(c) and (d) are correct.
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