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Refer to the arrangement of charges in F...

Refer to the arrangement of charges in Fig and a Gaussian surface of radius `R` with `Q` at the centre. Then

A

total flux through the surface of the spehre is `(-Q)/(epsilon_(0))`

B

field on the surface of the sphere is `(-Q)/(4piepsilon_(0)R^(2))`

C

flux through the surface of sphere due to `5Q` is zero.

D

field on the surface of spher due to `-2Q` is same everywhere.

Text Solution

Verified by Experts

The correct Answer is:
A,C
Total charge enclosed by the gaussians surface is `Q[=Q+(-2Q)]` so total flux tough the surface is `-(Q)/(epsilon_(0))` .As charge `+5Q` is outside the Gaussian surface the electric flux due ot it is zero .The electric field on the surface of the sphere is due to all the charges and is not consants beacuse the distribution of charges is not same for each and every point .
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