A conducting rod `PQ` of length `l=1.0m` is moving with a uniform speed `v2.0m//s` in a uniform magnetic field `B=4.0T` directed into the paper.
A capacitor of capacity `C=10muF` is connected as shown in figure. Then

Explanation

The motional emf is
`:. P.d` across the capacitor `= Blv = 4 xx 1 xx 2 = 8V`
`q = CV = 10 xx 8 = 80 muC`
`A` is `+Ve` w.r.t `B` (From fleming right hand rule)
The charge on plate `A` is `q_(A) = 80 muC`
The charge on plate `B` is `q_(B) = -80 muC`