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A 0.1 m long conductor carrying a curren...

A `0.1 m` long conductor carrying a current of `50 A` is perpendicular to a magentic field of `1.25 mT`. The mechanical power to move the conductor with a speed of `1ms^(-1)` is

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Power `P = Fv , P = Bilv , l = 0.1 m , i = 50`
`B = 1.25 xx 10^(-3) , v = 1m//sec, :. p = Bilv`
`= 1.25 xx 10^(-3) xx 50 xx0.1 xx1 , = 6.25 xx 10^(-3) , = 6.25 mW`
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NARAYNA-ELECTRO MAGNETIC INDUCTION-Level-II (H.W)
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