The loop `ABCD` is moving with velocity `'v'` towards right. The magnetic field is `4T`. The loop is connected to a resistance of `8 Omega`. If steady current of `2A` flows in the loop then value of `'v'` if loop has a resistance of `4 Omega`, is : (Given `AB = 30 cm, AD = 30 cm`)

Explanation

The induced emf in the loop is `e = Blv`
`e = B(AD)sin 37^(@) v = 4 xx 0.3 sin 37^(@)v`
Effective resistance of the circuit is
`R = (4+8) = 12 Omega`, Hence `i = (e)/(R ) = (Blv)/(R )`
`rArr 2 = (4 xx 0.3 xx sin 37^(@)v)/((4+8))`, `:. v = (100)/(3)m//s`