The self inductance of a coil having 200 turns is 10 mH. Compute the total flux linked with the coil. Also, determine the magnetic flux through the cross section of the coil, corresponding to current of 4 mA.

Explanation

Total magnetic flux linked with the coil,
`N phi = LI = 10^(-2) xx 4xx 10^(-3) = 4 xx 10^(-5)Wb`
`:.` Flux per turn, `phi = (4 xx 10^(-5))/(200) = 2 xx 10^(-7) Wb`