In the given circuit, find the current through the `5 mH` inductor in steady state.

Explanation

`5mH, 10 mH` are connected in parallel
`:.` Equivalent inductance
`L_("eq") = (5 xx 10)/(5+10) = (50)/(15) , =(10)/(3)mH`
Current at steady state, `I = (20)/(5) = 4A`
As `L_(1)` and `L_(2)` are in parallel
`I_(1) = ((L_(2))/(L_(1)+L_(2)))I, " "= ((10)/(10+5)) xx 4`
, `= (10)/(15) xx 4," "= (8)/(3) A m p`