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The flux linked with a coil is 0.8 Wb wh...

The flux linked with a coil is `0.8 Wb` when a `2` A current is flowing through it. If this current begins to increases at the rate of `400 A//s`, the induced `emf` in the coil will be

A

`20 V`

B

`40 V`

C

`80 V`

D

`160 V`

Text Solution

Verified by Experts

The correct Answer is:
D
`phi = Li rArr L = (0.8)/(2) = 0.4`
`e = L(di)/(dt) = 0.4 xx 400 = 160 v`
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