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An emf induced in a secondary coil is 10...

An emf induced in a secondary coil is `10000 V` when the current breaks in the primary. The mutual inductance is `5 H` and the current reaches to zero in `10^(-4) s` in primary. The maximum current in the primary before the breaks is

A

`0.2A`

B

`0.3A`

C

`0.4A`

D

`0.5 A`

Text Solution

Verified by Experts

The correct Answer is:
A
`e = L(di)/(dt) = 5((i_(1)-0)/(10^(-4)))`
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