A long solenoid of length L, cross secti...

A long solenoid of length `L`, cross section `A` having `N_(1)` turns has about its center a small coil of `N_(2)` turns as shows in Fig The mutual inductance of two circuits is

`(mu_(0)A(N_(1)//N_(2)))/(L)`

`(mu_(0)A(N_(1)N_(2)))/(L)`

`mu_(0) A(N_(1)N_(2))L`

`(mu_(0)A(N_(1)^(2)N_(2)))/(L)`

Text Solution

Verified by Experts

`phi_(2) = N_(2)B_(1)A " "` or `" " phi_(2) = N_(2)(mu_(0)N_(1)I_(1))/(L)A" "` or
`phi_(2) = (mu_(0)N_(1)N_(2)A)/(L)I_(1)`
Comparing with `phi_(2) = MI_(1)`, we get
`M_(2) = (mu_(0)N_(1)N_(2)A)/(L)`

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