Current growth in two `LR` circuits `(A)` and `(B)` is as shown in figure `(C )`. It follows that

Options

A. `R_(1) gt R_(2), L_(1) lt L_(2)`
B. `R_(1) gt R_(2), L_(1) = L_(2)`
C. `R_(1) = R_(2), L_(1) lt L_(2)`
D. `R_(1) lt R_(2), L_(1) gt L_(2)`

Explanation

`i_(0) = (V)/(R_(1)) = (V)/(R_(2)) rArr R_(1) = R_(2)`
`tau_(1) lt tau_(2) rArr (L_(1))/(R_(1)) lt (L_(2))/(R_(2)) rArr L_(1) lt L_(2)`