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Current growth in two LR circuits (A) an...



Current growth in two `LR` circuits `(A)` and `(B)` is as shown in figure `(C )`. It follows that

A

`R_(1) gt R_(2), L_(1) lt L_(2)`

B

`R_(1) gt R_(2), L_(1) = L_(2)`

C

`R_(1) = R_(2), L_(1) lt L_(2)`

D

`R_(1) lt R_(2), L_(1) gt L_(2)`

Text Solution

Verified by Experts

`i_(0) = (V)/(R_(1)) = (V)/(R_(2)) rArr R_(1) = R_(2)`
`tau_(1) lt tau_(2) rArr (L_(1))/(R_(1)) lt (L_(2))/(R_(2)) rArr L_(1) lt L_(2)`
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Knowledge Check

  • Current growth in two L-R circuits (b) and (c ) as shown in figure (a). Let L_(1), L_(2), R_(1) and R_(1) be the corresponding values in two circuits. Then

    A
    `R_(1)gt R_(2)`
    B
    `R_(1)=R_(2)`
    C
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    D
    `L_(1)lt L_(2)`

  • The current growth in two L-R circuits (b) and (c) is as shown in Fig. Let L_(1), L_(2), R_(1) and R_(2) be the corresponding values in two circuits. Then

    A
    `R_(1) gt R_(2)`
    B
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    C
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    D
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  • In the two circuits shown in figure

    A
    `R_(AB) = R_(CD) = (sqrt(3) + 2)Omega`
    B
    `R_(AB) = (sqrt(3) + 1) Omega`
    C
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    D
    `R_(AB) gt R_(CD)`

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