A `0.1 m` long conductor carrying a current of `50 A` is perpendicular to a magentic field of `1.25 mT`. The mechanical power to move the conductor with a speed of `1ms^(-1)` is

Options

A. `0.25 mW`
B. `6.25 m W`
C. `0.625 m W`
D. `1 W`

Answer

B

Explanation

`P = Fv = BIlv = 1.25 xx 10^(-3) xx 50 xx 0.1 xx 1W`
`6.25 xx 10^(-3)W = 6.25 mW`
An iterating alternating
`P = EI = (Blv)I`