A circuit `ABCD` is held perpendicular to the uinform magnetic field of `B = 5 xx 10^(-2)T` extending over the region `PQRS` and directed into the plane of the paper. The cicuit is moving out of the field at a uin form speed of `0.2 m s^(-1)` for `1.5 s`. During this time, the current in the `5 Omega` resistor is

Options

A. `0.6 mA` from `B` to `C`
B. `0.9 mA` from `B` to `C`
C. `0.9 mA` from `C` to `B`
D. `0.6 mA` from `C` to `B`

Answer

A

Explanation

`I = (Blv)/(R ), I = (5 xx 10^(-2) xx 0.3 xx 0.2)/(5)A = 0.6 mA`
Area and flux are decreasing. So, current flows to increase the flux. Clearly, current should be clockwise. So, it flows `B` to `C` through `5 Omega`.