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A specially uniform magnetic field of 0....

A specially uniform magnetic field of `0.080 T` is directed inot the plane of the page and perpendicular to it, as shown in the accompanying figure. A wire loop in the plane of the page has constant area `0.010 m^(2)`. The magnitude of the magnetic field decreases at a constant rate of `3.0 xx 10^(-4) T//s`. The magnitude and direction of the induced emf is

A

`3.0 xx 10^(-6) V` clockwise

B

`3.0 xx 10^(-6)V` anticlockwise

C

`2.4 xx 10^(-5) V` anticlockwise

D

`8.0 xx 10^(-4)V` clockwise

Text Solution

Verified by Experts

The correct Answer is:
A

`e = A(dB)/(dt) = 10^(-2) xx 3 xx 10^(-4) = 3 xx 10^(-6)`
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