A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is `0.2xx10^(-4)T`, then the emf developed between the two ends of hte conductor is

Options

A. `5 mu V`
B. `50 mu V`
C. `5 mV`
D. `50 mV`

Answer

B

Explanation

`E = (1)/(2) B omega R^(2)`
`= (1)/(2) xx 0.2 xx 10^(-4) xx 5 xx 1 xx1`
`= 0.5 xx 10^(-4) V = 54 xx 10^(-1) V`
`= 50 xx 10^(-6) V = 50 mu V`