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The flux linked with a coil at any insta...

The flux linked with a coil at any instant 't' is given by `phi = 10t^(2) - 50t +250`
The induced emf at `t = 3s` is

A

`10 V`

B

`190 V`

C

`-190 V`

D

`-10V`

Text Solution

Verified by Experts

The correct Answer is:
D
`E = -(d phi)/(dt)`
`= -(d)/(dt) (10 t^(2)-50 t + 250)`
`= -(20 t + 50)`
`e_("t = 3s") = -(20 xx 3 +50)V`
`= -10 V`
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