An ideal coil of 10H is connected in series with a resistance of `5(Omega)` and a battery of 5V. 2second after the connections is made, the current flowing in ampere in the circuit is

Options

A. `e`
B. `e^(-1)`
C. `1-e^(-1)`
D. `1-e`

Answer

C

Explanation

During the growth of current in `LR` circuit is given by `I = I_(0)(1-e^((R )/(L)t))`
or `I = (E)/(R )(1-e^(-(R )/(L)t)) = (5)/(5)(1-e^((5)/(10)xx2))`
`I = (I-e^(-1))`