In the circuit shown here, the point 'C' is kept connected to point 'A' till the current flowing through the circuit becomes constant. Afterward, suddenly, point 'C' is disconnected from point 'A' an connected to point 'B' at time t =0. Ratio of the voltage across resistance and the inductor at `t =L//R` will be equal to:

Options

A. `-1`
B. `(1-e)/(e)`
C. `(e)/(1-e)`
D. `1`

Answer

D

Explanation

Applying Kirchhoff's law in closed loop.
`-V_(R ) - V_(C ) = 0`
`rArr =V_(R )//V_(C ) = -1`
[Note: The sense of voltage drop has not been defined.] The answer could have been `1`.