Switches `S_(1), S_(2)` remain open and switch `S_(3)` remains closed for long time such that capacitor becomes fully charged and current in inductor coil becomes maximum, Now switches `S_(1), S_(2)` are simultaneously closed and`S_(3)` in simultaneously opened at `t=0`
Assume that battery and inductor coil are ideal

Find time `t gt 0`, when energy store in inductor would have minimum for the first time ?

Options

A. `(pi)/(4) xx 10^(-4) s`
B. `(pi)/(4) xx 10^(-4) s`
C. `(3pi)/(4) xx 10^(-4) s`
D. `pi xx 10^(-4) s`

Answer

C

Explanation

When energy store in inductor is minimum at that time energy strore in capacitor is maximum `|q_(max)|` first time when
`10^(4)t+(3pi)/(4) = (3pi)/(2) rArr t = (3 pi)/(4) xx 10^(-4)`