Six loops are formed of copper wire of the same cross-sectional area. Loops `1,2,3` and `4` are identical, loop `5` has the same area as the others but is longer. At the instant shown, all the loops are moving at the same speed in the directions indicated. A uniform and constant magnetic field points out of the page in region `I`, in region `II` there is no magnetic field. Ignore any interaction between the loops.

The corretc order of magnitudes of current in the loops is

Options

A. `I_(5) gt I_(4) = I_(1) gt I_(2) = I_(3)`
B. `I_(4) gt I_(1) gt I_(5) gt I_(2) = I_(3)`
C. `I_(5) = I_(4) gt I_(1) gt I_(2) = I_(3)`
D. `I_(4) = I_(1) gt I_(5) gt I_(2) = I_(3)`

Answer

D

Explanation

`(I_(2) = I_(3) = 0` and also `I_(1) = I_(4)`. The emf in loop `4` is larger than in loop `5`. Since area of loop `4` and loop `5` is same, circumference of loop `5` is larger in comparision to loop `4`. Hence resistance of loop `4` is lesser in comparision to loop `5`. Therefore
`I_(5) lt I_(4)`.
hence `I_(4) = I_(1) gt I_(5) gt I_(2) = I_(3)`.