Home
Class 12
PHYSICS
In the figure shown 'R' is a fixed condu...

In the figure shown `'R'` is a fixed conducting fixed ring of negligible resistance and radius `'a'` `PQ` is a uniform rod of resistance `r`. It is hinged at the centre of the ring and rotated about this point in clockwise direction with a uniform angular velocity `w`. These is a uniform magnetic filled of strength `'B'` ponting inwards. `'r'` is a stationary resistance

A

Current through `'r'` is zero.

B

Current through `'r'` is `(2B omega a^(2))/(5r)`.

C

Direction of current in external `'r'` is from centre to circumference.

D

Direction of current in external `'r'` is from circumference to centre. `k`

Text Solution

Verified by Experts

The correct Answer is:
B, D

Equivalent circuit :
Induced emf `e = (B omega r^(2))/(2) = ((B omega a^(2))/(2))`
(`Q` Radius a)
by nodal equation :
nodal
`4((X-e)/(r )) + ((X-0)/( r)) = 0`

`5X = 4e`
`Ϸ X = (4e)/(5) = (2B omega a^(2))/(5)` and `I = (X)/(r ) = (2B omega a^(2))/(5r)`
also direction of current in `'r'` will be towards negative terminal i.e., from rim to origin.
Alternating, by equivalent of cells (fig (ii)) :
`I = (e)/(r+(r )/(4)) = (4e)/(5r)`
Promotional Banner

Topper's Solved these Questions

  • ELECTRO MAGNETIC INDUCTION

    NARAYNA|Exercise Integer type questions|2 Videos
  • ELECTRO MAGNETIC INDUCTION

    NARAYNA|Exercise Level-I(H.W)|23 Videos
  • ELECTRO MAGNETIC INDUCTION

    NARAYNA|Exercise Comprehension Type Questions|22 Videos
  • ELECTRIC CHARGES AND FIELDS

    NARAYNA|Exercise EXERCISE -4|43 Videos
  • ELECTRO MAGNETIC WAVES

    NARAYNA|Exercise LEVEL-II(H.W)|14 Videos

Similar Questions

Explore conceptually related problems

A horizontal ring of radius r spins about its axis with an angular velocity omega in a uniform vertical magnetic field of magnitude B . The emf induced in the ring is

A and B are two points on a uniform ring of resistance R the /_ASCB=theta , whre C is the centre of the sign. The equivalent reisrtance between A and b

A conducting ring of radius r having charge q is rotating with angular velocity omega about its axes. Find the magnetic field at the centre of the ring.

A and B are two points on a uniform ring of resistance R . The /_ ACB = 90^@ , where C is the center of the ring. The equivalent resistance between A and B is.

There is a ring of radius r having linear charge density lambda and rotating with a uniform angular velocity omega. the magnetic field produced by this ring at its own centre would be

A conducting loop rotates with constant angular velocity about its fixed diameter in a uniform magnetic field, whose direction is perpendicular to that fixed diameter.

A conductor PQ , with PQ=r , moves with a velocity v in a uniform magnetic field of induced B . The emf induced in the rod is