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A coil of 30 turns of wire each of 10 cm...

A coil of `30` turns of wire each of `10 cm^(2)` area is placed with its plance perpendicular to a magnetic field of `0.1 T`. When the coil is suddenly withdraw from the field, a galvanometer connected in series with the coil indicated that a `10 mu C` charge passes around the circuit. The combined resistance of the coil and galvanometer is

A

`3 Omega`

B

`30 Omega`

C

`300 Omega`

D

`3000 Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
`q = (d phi)/(R ) = (NA(B_(1)-B_(2)))/(R )`
`10 mu c = (30 xx 10^(-3) (0.1 -0))/(R ), R = 300 Omega`
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Knowledge Check

  • A coil of area 100 cm^(2) having 50turns is perpendicular to a magnetic field of intensity 0.02T. The resistance of the coil is 2Omega . If t is removed from magnetic field in is the charge flown through the coil is:

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    D
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  • A rectangular coil of 25 turns, area of 25cm^(2) and resistance of 4 ohm//turn is placed perpendicular to a varying magnetic field, which changes at the rate of 500 T//s . The induced current in the coil is

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    C
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