A coil of `30` turns of wire each of `10 cm^(2)` area is placed with its plance perpendicular to a magnetic field of `0.1 T`. When the coil is suddenly withdraw from the field, a galvanometer connected in series with the coil indicated that a `10 mu C` charge passes around the circuit. The combined resistance of the coil and galvanometer is

Options

A. `3 Omega`
B. `30 Omega`
C. `300 Omega`
D. `3000 Omega`

Answer

C

Explanation

`q = (d phi)/(R ) = (NA(B_(1)-B_(2)))/(R )`
`10 mu c = (30 xx 10^(-3) (0.1 -0))/(R ), R = 300 Omega`