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A rectangular loop with a sliding connec...

A rectangular loop with a sliding connector of length `l = 1.0 m` is situated in a uniform magnetic field `B = 2T` perpendicular to the plane of loop. Resistance of connector is `r = 2 Omega`. Two resistances of `6Omega` and `3Omega` are connected as shown in . The external force required to keep the connetor moving with a constant velocity `v = 2 m s^(-1)` is

A

`6N`

B

`4N`

C

`2N`

D

`1N`

Text Solution

Verified by Experts

The correct Answer is:
B
`F = (B^(2)l^(2)v)/(R_(P))` here `R_(P) = (6 xx 3)/(6+3) = 2 Omega`
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